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JAMB UTME 2018

JAMB Chemistry 2018 past questions

6 objective questions from the 2018 JAMB Chemistry paper. Answer each one, then reveal the answer and explanation.

All JAMB Chemistry past questions

  1. Question 1

    Mole concept

    How many moles are there in 300 g of calcium trioxocarbonate(IV) (CaCO₃)? [Ca = 40, C = 12, O = 16]

    1. Option A: 6 mol
    2. Option B: 1.5 mol
    3. Option C: 3 mol
    4. Option D: 30 mol
    Show the answer to question 1

    Answer: C, 3 mol

    Moles = mass ÷ molar mass = 300 ÷ 100 = 3 mol.

  2. Question 2

    Chemical symbols

    What is the chemical symbol of iron?

    1. Option A: Fe
    2. Option B: Ir
    3. Option C: I
    4. Option D: F
    Show the answer to question 2

    Answer: A, Fe

    Iron is Fe, from its Latin name ferrum.

  3. Question 3

    Periodic table

    In which group of the periodic table is chlorine found?

    1. Option A: Group III
    2. Option B: Group VII
    3. Option C: Group IV
    4. Option D: Group V
    Show the answer to question 3

    Answer: B, Group VII

    Chlorine (configuration 2, 8, 7) is in Group VII.

  4. Question 4

    Acids, bases and salts

    A base that dissolves in water is called

    1. Option A: an alkali
    2. Option B: a salt
    3. Option C: an indicator
    4. Option D: an acid
    Show the answer to question 4

    Answer: A, an alkali

    A soluble base is an alkali.

  5. Question 5

    Gas laws

    A fixed mass of gas occupies 360 cm³ at a pressure of 5 atm. What volume will it occupy at 10 atm if the temperature stays constant?

    1. Option A: 720 cm³
    2. Option B: 360 cm³
    3. Option C: 18000 cm³
    4. Option D: 180 cm³
    Show the answer to question 5

    Answer: D, 180 cm³

    By Boyle's law, P₁V₁ = P₂V₂, so V₂ = 5 × 360 ÷ 10 = 180 cm³.

  6. Question 6

    Atomic structure

    An atom of hydrogen has atomic number 1 and mass number 1. How many neutrons are in its nucleus?

    1. Option A: 1
    2. Option B: 2
    3. Option C: 3
    4. Option D: 0
    Show the answer to question 6

    Answer: D, 0

    Neutrons = mass number − atomic number = 1 − 1 = 0.

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